![]() ![]() If the intersection of any two perpendicular chords divides one chord into lengths a and b and divides the other chord into lengths c and d, then a 2 + b 2 + c 2 + d 2 equals the square of the diameter.If the intersection of any two chords divides one chord into lengths a and b and divides the other chord into lengths c and d, then ab = cd.Among all the circles with a chord AB in common, the circle with minimal radius is the one with diameter AB.The diameter is the longest chord of the circle.An inscribed angle subtended by a diameter is a right angle (see Thales' theorem). ![]()
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